Roméo Lavia - salary, contract & career earnings
Roméo Lavia earns AU$128,520 per week and AU$6,683,040 per year playing for Chelsea. Roméo Lavia has earned AU$32,024,047 in career wages. Current deal expires 30 June 2030.
Earns more than 54.2% of the 441 Premier League players we hold a wage for.
Earnings over time
Weekly wage by contract year, over the seasons we hold a wage for
Contract history
Tap a column heading to re-rank| YEAR | WEEKLY WAGE | YEARLY SALARY | CLUB | LEAGUE | POSITION | AGE | CONTRACT EXPIRY |
|---|---|---|---|---|---|---|---|
| 2027 | AU$128,520 | AU$6,683,040 | Chelsea | Premier League | DM | 21 | 30 June 2030 |
| 2026 | AU$128,520 | AU$6,683,040 | Chelsea | Premier League | DM | 21 | 30 June 2030 |
| 2025 | AU$137,970 | AU$7,174,440 | Chelsea | Premier League | DM | 21 | 30 June 2028 |
| 2024 | AU$137,970 | AU$7,174,440 | Chelsea | Premier League | DM | 19 | 30 June 2030 |
| 2023 | AU$71,820 | AU$3,734,640 | Southampton | Championship | DM | 18 | 30 June 2027 |
| 2022 | AU$10,773 | AU$560,196 | Manchester City | Premier League | DM | 17 | 30 June 2024 |
| 2021 | AU$274 | AU$14,251 | Manchester City | Premier League | DM, M (C) | 16 | 30 June 2024 |
Contract timeline
Deals signed and when they expire
Wage rank at Chelsea
Roméo Lavia is the 22nd highest earner in the squad
Cumulative career earnings
Running total by year, over the seasons we hold a wage for
Frequently asked questions
Roméo Lavia, Chelsea
How much does Roméo Lavia earn per week?
Roméo Lavia earns AU$128,520 per week playing for Chelsea.
What is Roméo Lavia's yearly salary?
Roméo Lavia's yearly salary is AU$6,683,040.
What is Roméo Lavia's net worth?
We publish career earnings rather than net worth. Roméo Lavia has earned AU$32,024,047 in wages across 7 recorded seasons.
When does Roméo Lavia's contract expire?
Roméo Lavia's current contract with Chelsea expires on 30 June 2030.
What position does Roméo Lavia play?
Roméo Lavia plays as a DM for Chelsea in the premier-league.
How old is Roméo Lavia?
Roméo Lavia is 21 years old.