Nathaniel Brown - salary, contract & career earnings
Nathaniel Brown earns £32,000 per week and £1,664,000 per year playing for FC Bayern München. Nathaniel Brown has earned £3,286,400 in career wages. Current deal expires 30 June 2030.
Earns more than 62.5% of Bundesliga players.
Earnings over time
Weekly wage by contract year, over the seasons we hold a wage for
Contract history
Tap a column heading to re-rank| YEAR | WEEKLY WAGE | YEARLY SALARY | CLUB | LEAGUE | POSITION | AGE | CONTRACT EXPIRY |
|---|---|---|---|---|---|---|---|
| 2027 | £32,000 | £1,664,000 | FC Bayern München | Bundesliga | D/WB L | 22 | 30 June 2030 |
| 2026 | £32,000 | £1,664,000 | Eintracht Frankfurt | Bundesliga | D/WB L | 22 | 30 June 2030 |
| 2025 | £15,000 | £780,000 | Eintracht Frankfurt | Bundesliga | D/WB L | 22 | 30 June 2028 |
| 2024 | £15,000 | £780,000 | 1. FC Nürnberg | 2. Bundesliga | D/WB L | 20 | 30 June 2029 |
| 2023 | £820 | £42,640 | 1. FC Nürnberg | 2. Bundesliga | D/WB L, DM | 19 | 30 June 2024 |
| 2022 | £380 | £19,760 | 1. FC Nürnberg | 2. Bundesliga | D L, DM | 18 | 30 June 2022 |
Contract timeline
Deals signed and when they expire
Wage rank at FC Bayern München
Nathaniel Brown is the 19th highest earner in the squad
Cumulative career earnings
Running total by year, over the seasons we hold a wage for
Frequently asked questions
Nathaniel Brown, FC Bayern München
How much does Nathaniel Brown earn per week?
Nathaniel Brown earns £32,000 per week playing for FC Bayern München.
What is Nathaniel Brown's yearly salary?
Nathaniel Brown's yearly salary is £1,664,000.
What is Nathaniel Brown's net worth?
We publish career earnings rather than net worth. Nathaniel Brown has earned £3,286,400 in wages across 5 recorded seasons.
When does Nathaniel Brown's contract expire?
Nathaniel Brown's current contract with FC Bayern München expires on 30 June 2030.
What position does Nathaniel Brown play?
Nathaniel Brown plays as a D/WB L for FC Bayern München in the bundesliga.
How old is Nathaniel Brown?
Nathaniel Brown is 22 years old.